[原创]2006年6月Math机经讨论稿第11篇(164-178) 6.27日

cournot

17178.
        一个组织有60%的人申请CPA，这其中有40%是male,有80%male(m*80%=40%=>m=50%)申请CPA，问：这里面百分之多少的female申请CPA？答案: 40%=20%/50% 注意：是求申请CPA的female占female

	M	F
CPA	40%	20%	60%
N.cpa			40%
	50%	50%

这个题GWD（滔滔版）有类似的：

Gwd-1-17: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females? =16%/64%=25%

	M	F
E	48%	16%	64%
N.E			36%

mba06

"这其中有40%是male"

this is tricky. need to see the original English. we don't know whether this 40% is of the 60% or of the whole people in the orgnization.

kdjd

175. DS: a,b都是整数,问a*b的值?
1) a*b能被6整除
2) a, b都是质数
答案:C

177. XY坐标系,一个圆C和一条线K,问是否相交(就这些条件!)
1) 圆C在Y轴的INTERCEPT是-2和2,
2) 线K在X轴的INTERCEPT –3/2
答案: E

这两道不太明白。175我觉得推不出来，177我觉得1和2一起肯定能推出相交

moomoo

以下是引用wantfly在2006-6-28 10:30:00的发言：

同问，我算出也是15/40？

Ditto. 37.5%

moomoo

以下是引用kdjd在2006-7-7 21:59:00的发言：

175. DS: a,b都是整数,问a*b的值?
1) a*b能被6整除
2) a, b都是质数
答案:C

177. XY坐标系,一个圆C和一条线K,问是否相交(就这些条件!)
1) 圆C在Y轴的INTERCEPT是-2和2,
2) 线K在X轴的INTERCEPT –3/2
答案: E

这两道不太明白。175我觉得推不出来，177我觉得1和2一起肯定能推出相交

175: since a/b are prime numbers, neither a or b can be multiples of 6;

        thus, one of a,b has to be multiples of 2, since a,b are prime numbers, one of a,b has to be 2;

        likewise, one of a,b has to be 3.

177: just don't assume center of C is at origin.

moomoo

以下是引用nacl在2006-6-28 9:11:00的发言：
同意 36%/70%. 组织中申请CPA的female的百分比/总的female百分比

Ditto. Looks like 11th floor got confused.

baggiojia

同问!

我觉得可能是题目不全.

到底是问CPA female比总人数还是比总female数?