请教一个数学题

RamosZou

If the positive integer n is added to each of the integers 69, 94, and 121, what is the value of n?
(1) 69 + n and 94 + n are the squares of two consecutive integers.
(2) 94 + n and 121 + n are the squares of two consecutive integers.

答案是D

这个题目是啥意思啊，没看懂啊

请各位大神   不吝赐教啊   感激不尽

windowshade

k+1^2-k^2=94-69=>k=12 integer=>n=75 integer
(2) ..=121-94=27=>k=13 integer =>n=75 integer

RamosZou

windowshade 发表于 2016-11-5 03:49
k+1^2-k^2=94-69=>k=12 integer=>n=75 integer
(2) ..=121-94=27=>k=13 integer =>n=75 integer

能否请大神解释一下，这题目是啥意思啊？  拜托啦！

啦啦噜啦啦

这题说的是：（69+n) 和 （94+n） 是两个数的各自的平方，而且这两个数是两个连续的数