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请教两题

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楼主
发表于 2003-8-12 09:20:00 | 只看该作者

请教两题

at a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. if the night crew has 4/5 as many workers as teh day crew, what fraction of all the boxes loaded by the two crews did theday crew load?
答案为5/8

in a certain game, a large container is filled wiht red, yellow, green, and blue beads worth, respectively, 7,5,3,2 points each. a number o fbeads are then removed from the container. if the product of the point values of the removed beads is 147,000, how many red beads were removed?
答案为2,

x is 40% ryegrass and 60% bulegrass by weight; y is 25% ryegrass and 75%fescue. if mixture of x and y contains 30% ryegrass, what percent of the weight of  this mixture is x?
答案:33(1/3)%
请指教一下!谢谢!
沙发
发表于 2003-8-12 10:09:00 | 只看该作者
社白天每个工人搬箱数为d晚上每个工人搬箱为n  n=3/4d    人数之比为N=4/5D
Dd/(Nn+Dd)=5/8

(40%x+25y)/(x+y)=30%  2x=y   
x/(x+y)=1/3=33(1/3)%

板凳
发表于 2003-8-12 10:32:00 | 只看该作者
第1题

设白天有Y人,每人装卸Y箱,则白天装卸XY箱,晚上装卸(3/4)(4/5)XY, 则白天装卸的比例为XY/(XY+3/5XY)=5/8

第2题
147000=7^2*3*5^3*2^3,因此红球2个。

第3题

X中 40%ryegrass    60% bulegrass
Y中  25%ryegrass    75%fescue

则 (40%X+25%Y)/(X+Y)=30%
表示为 (15%X+25%(X+Y))/(X+Y)=30%, X/(X+Y)可算出1/3
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