逻辑JJ Q125，考古，质疑答案！

LexieZH

Q125.(by jennyicejy（710）)一个说rat关在一起，就会aggressive; 但是有一种猕猴（反正一直猴子，不认识那词）关在一个，不aggressive. 结论，猴子没有rat aggressive. 问support。我选了猕猴是猴子中最aggressive的。

考古：

In 1960’s studies ofrats, scientists found that crowding increases the number of attacks among theanimals significantly.  But in recentexperiments in which rhesus monkeys were placed in crowded conditions, althoughthere was an increase in instances of “coping” behavior—such as submissivegestures and avoidance of dominant individuals—attacks did not become any morefrequent.  Therefore it is not likely that,for any species of monkey, crowding increases aggression as significantly aswas seen in rats.
Which of the following,if true, most strengthens the argument?

All the observed     forms of coping behavior can be found among rhesus monkeys living in     uncrowded conditions.

In the studies of     rats, nondominant individuals were found to increasingly avoid dominant     individuals when the animals were in crowded conditions.

Rhesus monkeys respond with aggression to a     wider range of stimuli than any other monkeys do.

Some individual     monkeys in the experiment were involved in significantly more attacks than     the other monkeys were.

Some of the coping     behavior displayed by rhesus monkeys is similar to behavior rhesus monkeys     use to bring to an end an attack that has begun.



各位，虽然JJ里面答案是C，但是我比较想不明白
下面是我的想法，大家看看对不……
D和E有some~~~属于无意义概率
B讨论老鼠的实验，无关选项
C是说恒河猴和其他所有猴子的比较，但题目说的是整个猴子都会怎样怎样啊……所以我疑惑
A说这猴子在不拥挤的地方也是这种反映，那么不是就证明它们不想老鼠或者其他动物那样会聚众就闹事儿吗？

弗拉多

这题的关键在于怎么理解“it is not likely that,for any species of monkey, crowding increases aggression as significantly as was seen in rats.”

尤其是当中的“for any species of monkey”到底是修饰什么。

结论如果是所有的猴子都没有老鼠有攻击性，但是实验里用的只有那种猴子。

C选项那种猴子是猴子中最有攻击性的了，言外之意那种猴子都OK其他猴子更没问题，加强。

反之结论如果是并不是所有的猴子都像老鼠一样，那自然就应该按楼主想得选A。

个人倾向于选C。

-- by 会员 暮云春树 (2011/10/16 0:39:48)

+1

LexieZH

感谢各位大侠讨论分析，我昨儿也想了好久，觉得，从整体来看，题目是要说通过恒河猴的聚众反应来看，似乎猴子这种动物(包括所有种类的猴子)就不像老鼠那么一聚众就闹事儿。那么按照C的说法，恒河猴已经是猴子里面最最aggressive的了，也就是说其他种类的猴子更加不爱闹事儿。

A的说法呢，我想是不是也可以理解成，“猴子的那种避免与权力领导产生冲突的特征与在不在聚众环境无关，他们本来就是那个样子的”，所以对题目没有加强的作用。这样A也成了无关选项……

恩……LZ是觉得答案给C应该就有C的道理，不知道以上的理解对不对~

谢谢不倒翁要杀鸡，暮云春树，limingdaili等童鞋的提点呀！！

Heather_Lau

但是大家不觉得整篇paragraph都是在讲crowding是否会increase aggression的吗?跟其他的猴子有毛关系啊?而且取非的话,如果没在那些uncrowded conditions中发现这种behavior,那么能说明aggression是由于crowding引起的.
那么就weaken结论了啊!!!!!

limingdaili

楼主，我一直琢磨你提出的这个问题，昨天还真心认为A对，但是今天我认为C对，因为it is not likely that,for any species of monkey, crowding increases aggression as significantly as was seen in rats. 这里面any species应该是说所有种类，由于前面是否定not，所以用any.
此题目的应该是考推理范围扩大后如何加强。除猕猴外所有猴子侵略性<猕猴侵略性<rats侵略性，所以加强结论。别再纠结了。上面有一哥们把英文解释也贴出来了，估计老外没咱们想这么多。

不倒翁要杀鸡

个人觉得有点像GAP的感觉

不倒翁要杀鸡

网上搜到的：

If you think that E might be the right answer, determine whether it neutralizes or counters a reasonable objection. Thus, the converse of E should clearly weaken the arguement. Whether or not the coping behaviour is similar to gestures used to end an attack seems irrelevant to the strength of the argument. If you disagree, explain how E could be relevant.

The most evident assumption made stems from the broadening of the scope of the evidence (rhesus monkeys) to the conclusion (all monkeys)

_________________
Kevin Armstrong
GMAT Instructor
Gmatclasses
Madrid

marksze

我的理解是最后的any monkey，所以选C，R monkey已经是最aggressive的了

Heather_Lau

结论提出主干嘛,it is not likely that crowding increases aggression as significantly as was seen in rats.意思很明显啦,crowding是关键词,那么肯定就是说uncrowded的地方也有这些aggression,才能strengthen.
C感觉是比较的category错误.

暮云春树

这题的关键在于怎么理解“it is not likely that,for any species of monkey, crowding increases aggression as significantly as was seen in rats.”

尤其是当中的“for any species of monkey”到底是修饰什么。

结论如果是所有的猴子都没有老鼠有攻击性，但是实验里用的只有那种猴子。

C选项那种猴子是猴子中最有攻击性的了，言外之意那种猴子都OK其他猴子更没问题，加强。

反之结论如果是并不是所有的猴子都像老鼠一样，那自然就应该按楼主想得选A。

个人倾向于选C。