数学机经16题 median salary for the company

ouying0501

我记得是GWD上的题，因此搜索了一下。原题应该是：
In a company 60% of the employees earn less than $50,000 a year, 60% of the employees earn more than $40,000 a year, 11% of the employees earn $43,000 a year and 5% of the employees earn $49,000 a year. What is the median salary for the company?
a) 43.000
b) 45.500
c) 46.000
d) 49.000
e) 50.000


In a company 60% of the employees earn less than $50,000 a year, 60% of the employees earn more than $40,000 a year, 11% of the employees earn $43,000 a year and 5% of the employees earn $49,000 a year. What is the median salary for the company?

60% of the employees earn less than $50,000 a year
=> 40% earn greater than 50,000 a year.

60% of the employees earn more than $40,000 a year
=> 40% earn less than 40,000 a year..

Let there are 100 employess
then, to calculate median we need salary of 50th employee and 51th employee.

Then, median = (salary of 50th employee + salary of 51th employee)/2
40 people<40000 $40,000 20 people $50,000 40 people > 50,000
--------------------------*----------------*----------------------

Salary of 11 people = 43,000
Salary of 5 people = 49,000
whtever, be the case, 50th and 51th salary would be 43,000 and 43,000

Hence, median=（2*43.000）/2=43.000

希望对大家有帮助。

sly198555

如果是求平均数呢？

ouying0501

应该是前面五套之内吧，我也只做了那么几套。具体我就不记得了，我是直接在谷歌上搜索的。

gmat考750

楼主这是哪套啊？

baohan0915

谢谢！~

ccronaldo

原题好像不是这个数据 这个数据算出来中间那段是20人 那么拥有十一人的那个salary当然是中位数 可是如果中间那段的人数是大于11的两倍 比如23人呢 是不是就没法算出中位数了？

mimipo

顶！！

lien331222

ding

chandlerlfh

of course A!

Summer1999