ChaseDream
搜索
返回列表 发新帖
查看: 704|回复: 3
打印 上一主题 下一主题

求OG12 DS128题详解

[复制链接]
跳转到指定楼层
楼主
发表于 2010-10-2 20:24:20 | 只看该作者 回帖奖励 |正序浏览 |阅读模式
如下题,这题怎么解释?看OG的答案看不太明白。
A school administor will assign each student in a group of n students to one of m classrooms.If 3<m<13<n,is it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it?
(1)It is possible to assign each of 3n students to one of m classrooms so that each classroom has the same number of students assigned to it.
 (2)  It is possible to assign each of 13n studetns to one of m classrooms so that each classroom has the same number of students assigned to it.
收藏收藏 收藏收藏
地板
发表于 2012-5-16 10:27:33 | 只看该作者
有点怕DS
板凳
发表于 2012-5-16 10:27:15 | 只看该作者
这种题好阴险,考试遇到这种题肯定想不到。。。。。。。。。。。。。。
沙发
发表于 2010-10-13 17:10:29 | 只看该作者
FW from: http://forum.chasedream.com/GMAT_Math/thread-433703-1-1.html?SearchText=OG12 DS 128
题目说了半天,其实就是问,

3<m<13<n, n是否能整除m?条件1,3n能整除m;条件2,13n能整除m。

这就简单了,m的取值可以是2,3,4,5,6,7,8,9,10,11,12,这样,根据条件1,3n能整除m,无法判断出n是否能整除m,因为m有可能是6,9,或者12。但是条件2,13n可能 整除m的话,并且m的取值中没有能整除13被13整除的,这就说明13n中的n一定正整除m。所以条件2可以判断
您需要登录后才可以回帖 登录 | 立即注册

手机版|ChaseDream|GMT+8, 2025-2-15 20:38
京公网安备11010202008513号 京ICP证101109号 京ICP备12012021号

ChaseDream 论坛

© 2003-2023 ChaseDream.com. All Rights Reserved.

返回顶部