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129、一个直角三角形ABC, B为直角, F为AC上的一点,问F是否平分角
1.AF=BF
2 F 为BC中点
更正原题:一个直角三角形ABC, B为直角, F为AC上的一点,问BF是否等于FC
1.AF=BF
2 F 为BC中点 (此项更正是基于JJ内另一道重复题)
解:1)AF=BF,则∠FAB=∠FBA,用90°同时减去方程左右两边,得∠FCB=∠FBC,即BF=FC
2)F为BC中点,则AF=FC=BF
答案:D |
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