- UID
 - 1472021
 
- 在线时间
 -  小时
 
- 注册时间
 - 2020-10-22
 
- 最后登录
 - 1970-1-1
 
- 主题
  
- 帖子
  
- 性别
 - 保密
 
 
 
 
 
 
 | 
解答怎样得到30k+29 
 
两个式子:n=5k+4, n=6k+5 
 
Positive integer n is divided by 5, the remainder is 4 --> n=5a+4, where a is the quotient --> 4, 9, 14, 19, 24, 29, ... 
Positive integer n is divided by 6, the remainder is 5 --> n=6b+5, where b is the quotient -->5, 11, 17, 23, 29 , .... 
 
There is a way to derive a general formula for n (of a type n=kx+r, where x is divisor and r is a remainder) based on the above two statements: 
 
Divisor x would be the least common multiple of above two divisors 5 and 6, hence x=30. 
 
Remainder r would be the first common integer in above two patterns, hence r=29. 
 
Therefore general formula based on both statements is n=30k+29.  |   
 
 
 
 |