请教一道数学--prep中的，实在看了答案也不懂。拜托了·~~~~~

rainbowyc

169.16735-!-item-!-187;#058&010875

If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of aⁿ, what is the value of a ?



(1)aⁿ = 64



(2)n = 6

--------------------------------------------------------------------------------------------------------------------------------------------------------【答案】B



【思路】(1)
2的6次= 64 , 4的3次=64 , 8的2次=64 , not sufficient
(2) n = 6 ,
2的6次= 64 , sufficient

the product of the first 8 positive integers is a multiple of aⁿ,   前8个什么数啊？

rainbowyc

额。。，，，，没人，，，只能把答案背下来了

treewing929

我覺得條問題可能錯

范小歪

就是说8的阶乘是a^n的一个倍数~~

goodlolo

the product of the first 8 positive integers 就是說1*2...8

xiangjiaopi

169.16735-!-item-!-187;#058&010875

If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of aⁿ, what is the value of a ?



(1)aⁿ = 64



(2)n = 6

--------------------------------------------------------------------------------------------------------------------------------------------------------【答案】B



【思路】(1)
2的6次= 64 , 4的3次=64 , 8的2次=64 , not sufficient
(2) n = 6 ,
2的6次= 64 , sufficient

the product of the first 8 positive integers is a multiple of aⁿ,   前8个什么数啊？

-- by 会员 rainbowyc (2012/2/10 17:54:06)

意思是：前8个正整数的积是aⁿ 的倍数。

即aⁿ  是1*2*3....*8=2^7*3^2*5*7的一个约数~~