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feifei-24

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楼主
发表于 2004-9-10 12:40:00 | 只看该作者

feifei-24


24. The interstitialadj.空隙的, 裂缝的, 形成空隙的 nucleus, a subregion of the brain’s hypothalamus, is typically smaller for male cats than for female cats. A neurobiologist performed autopsies on male cats who died from disease X, a disease affecting no more than .05 percent of male cats, and found that these male cats had interstitial nuclei that were as large as those generally found in female cats. Thus, the size of the interstitial nucleus determines whether or not male cats can contract disease X.


Which one of the following statements, if true, most seriously weakens the argument? d


(A) No female cats have been known to contract disease X, which is a subtype of disease Y.


(B) Many male cats who contract disease X also contract disease Z, the cause of which is unknown.


(C) the interstitial nuclei of female cats who contact disease X are larger than those of female cats who do not contract disease X.


(D) Of 1,000 autopsies on male cats who did not contract disease X, 5 revealed interstitial nuclei larger than those of the average male cat. 只有这项有提到interstitial nuclei


(E) The hypothalamus is known not to be causally linked to disease Y, and disease X is a subtype of disease Y.


我选d


答案是e


e中有无关的内容,我直接就排除了


NN给讲讲

沙发
发表于 2004-9-10 19:28:00 | 只看该作者
d的内容其实是原文的5%的复述,没有任何削弱作用。e其实是它因削弱。
板凳
发表于 2005-8-16 10:20:00 | 只看该作者

我的理解:


原文是在说正常的公猫中interstitial nuclei 比正常的母猫的interstitial nuclei小,感染一种X病的概率不超过0.05%,在这些染X病的公猫中interstitial nuclei与正常的母猫的interstitial nuclei一样大(注意没有跟公猫比较);D选项在说正常情况下,每1000只没有染病公猫中就有5只(概率大于等于原文概率)公猫的interstitial nuclei 比正常的公猫interstitial nuclei的平均值大,我认为D错在没有跟母猫比较;假如D改为“Of 1,000 autopsies on male cats who did not contract disease X, 5 revealed interstitial nuclei as larger as those of the average female cat."那么就是削弱;D选项应该不是简单的对原文的复述。


[此贴子已经被作者于2005-8-16 10:22:14编辑过]
地板
发表于 2005-9-25 22:45:00 | 只看该作者

完全同意楼上的看法。这道题很恶心,E是完美的断桥型没意见,选项为保证严密性,还给出了“独桥”的条件。D要是提供了和female cat的比较,则也是完美的它因削弱。D选项要是按照GMAT并不严密的逻辑,应该也是正确选项。


5#
发表于 2005-11-10 18:35:00 | 只看该作者

20-30晕阿!前几个连着错!唉!


这道对了!庆幸!


D项有加强的意思!因为它是顺着原文说得!


3楼的意见我是同意的


总之!难啊!

6#
发表于 2005-12-18 16:58:00 | 只看该作者
搂主看看数字有没有标错,是0。05还是0。5 差很多的哦
7#
发表于 2006-3-22 02:56:00 | 只看该作者
我认为D是无关项.说1000只没有感染的公猫中有5只的...要比公猫的平均大点,这有什么意义呢?应该和母猫的...相对比才行.而且大于平均是很正常的,只有大于平均和小于平均才能产生中间的平均.
8#
发表于 2007-1-9 14:59:00 | 只看该作者

一直困惑了好久,今天一看到这个观点才恍然大悟。

我同意你的观点!

——可以看出,自己读题还是不够仔细啊!我一直在潜意识中认为是跟母猫比呢

9#
发表于 2007-1-9 15:00:00 | 只看该作者
以下是引用wingkim在2005-8-16 10:20:00的发言:

我的理解:

原文是在说正常的公猫中interstitial nuclei 比正常的母猫的interstitial nuclei小,感染一种X病的概率不超过0.05%,在这些染X病的公猫中interstitial nuclei与正常的母猫的interstitial nuclei一样大(注意没有跟公猫比较);D选项在说正常情况下,每1000只没有染病公猫中就有5只(概率大于等于原文概率)公猫的interstitial nuclei 比正常的公猫interstitial nuclei的平均值大,我认为D错在没有跟母猫比较;假如D改为“Of 1,000 autopsies on male cats who did not contract disease X, 5 revealed interstitial nuclei as larger as those of the average female cat."那么就是削弱;D选项应该不是简单的对原文的复述。


一直困惑了好久,今天一看到这个观点才恍然大悟。

我同意你的观点!

——可以看出,自己读题还是不够仔细啊!我一直在潜意识中认为是跟母猫比呢

10#
发表于 2007-10-23 04:10:00 | 只看该作者

我想问一下,为什么把C排除了,如果雌猫患病,致使the size of the interstitial nucleus变大,那么患病的公猫和患病的母猫比,一定size比较小了,和拿患病的公猫的 size与不患病的母猫比一样大不同,就不能知道公猫是否患病了。为什么这个假设不是削弱呢?

请大家有想法的告诉我,我整个人都

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