我的结果是0,1,3,4, 只有这四种可能性, 因为a(n) + ....+a3= a(n-1) - a1. so a(n) + ....+a3 + a2+a1 = a(n-1) + a2 but n>3. a(n) can be -2, -1, 1, 2 when n>3. So the sum can be 0, 1, 3, 4; when n =3, sum =4, n<3, sum can be 1 or 3. I can only find this four possibility. 不知道有没有算错