ChaseDream
搜索
返回列表 发新帖
查看: 3572|回复: 2
打印 上一主题 下一主题

prep 94, Help Pls

[复制链接]
跳转到指定楼层
楼主
发表于 2009-12-17 01:06:54 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
A company plans to assign identification numbers to its employees.  Each number is to consist of four different digits from 0 to 9, inclusive, except that the first digit cannot be 0.  How many different identification numbers are possible?
(A) 3,024
(B) 4,536
(C) 5,040
(D) 9,000
(E) 10,000

I choose D.
here is the solution from prep notes
Each number is to consist of four different digits  為四位數
the first digit cannot be 0 故有1到9 九個數字
the SECOND digit 可以為0但是因為the first digit用到一個數字 所以剩下九個數字
the THIRD digit 剩下八個數字
the fourth digit 剩下七個數字
9×9×8×7=4536

however, I think the number on each digit can be repeated. For example 2222, 1111 are valid ID number. So it should be 9*10*10*10=9000
收藏收藏 收藏收藏
沙发
发表于 2009-12-17 02:57:21 | 只看该作者
consist of four different digits。。。
楼主,是different digits哦,所以重复是不行的=。=
板凳
 楼主| 发表于 2009-12-17 09:36:30 | 只看该作者

... jing ran mei kan dao, diu ren le, bu hao yi
您需要登录后才可以回帖 登录 | 立即注册

Mark一下! 看一下! 顶楼主! 感谢分享! 快速回复:

手机版|ChaseDream|GMT+8, 2024-11-30 08:49
京公网安备11010202008513号 京ICP证101109号 京ICP备12012021号

ChaseDream 论坛

© 2003-2023 ChaseDream.com. All Rights Reserved.

返回顶部