涛涛GWD2-30？

ddcat910 · 发表于 2006-6-9 11:01:00

Q30:

E

B C

A D

怎么图形不在了？ABCD是正方形，AB=BC=CD=AD=1，CE=1，BE=DE （答案是B－猜对了可算不出来）

In the figure, each side of square ABCD has length 1, the length of line segment CE is 1, and the length of line segment BE is equal to the length of line segment DE. What is the area of the triangular region BCE?

A. 1/3

B. (Ö2)/4

C. 1/2

D. (Ö2)/2

E. 3/4

ddcat910 · 发表于 2006-6-9 11:39:00

DINGDINGDING

yaoyao99 · 发表于 2006-6-9 11:52:00

Please list the question number in the title (e.g. GWD-2-31).

Someone asked this a few days ago. BCE = (BED - BCD) / 2

ddcat910 · 发表于 2006-6-9 12:14:00

Question number is GWD-2-30!

不好意思喔1

ddcat910 · 发表于 2006-6-10 06:16:00

ding again!!!

yaoyao99 · 发表于 2006-6-10 11:16:00

BCE = (BED - BCD) / 2

ddcat910 · 发表于 2006-6-10 12:27:00

麻烦能说仔细一点吗？好让我死了明白啊！

yaoyao99 · 发表于 2006-6-11 06:41:00

BE = ED, BC = CD, CE = CE => BCE = ECD
BCE = BED - BCD - ECD => BCE = BED - BCD - BCE => 2BCE = BED - BCD => BCE = (BED - BCD) / 2
You can get the area of BCD because BCD = ABCD/2
You can also get the area of BCD = BD * (CE + CA * 0.5) / 2

ddcat910 · 发表于 2006-6-11 07:25:00

谢谢斑竹！

我把abcde看作是立体的啦！

现在全明白了！

严重感谢！！！

yaoyao99 · 发表于 2006-6-11 07:28:00

Umum, the graph in GWD is very misleading. Try drawing it out on paper and then you'll realize everything is on the same plane.

涛涛GWD2-30？

涛涛GWD2-30？

所属分类: GMAT考试

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