本月jj55，来呀！

55. Sequence 2, 7, 22,…after the first three terms, each term is three times the previous term plus 1, a(n+1)=3an + 1. What is the sum of tens digit and tens digit of the 35 term?
                

讨论：我多写了几项，发现，十位数的规律是2.6.0.0，四位数循环。个位数就是2.7循环。所以，35项的个位数：(2+7)*17+2=155, 留5，进15。十位数：(2+6+0+0)*8+8=72. 再加上进位72+15=87，留7进8。所以，十位数是7