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At a dinner party, 5 people are to be seated around a circular table.Two seating arrangements are considered different only when the positions of the people are different relative to each other.What is the total number of different possible seating arrangements for the group?
(A) 5
(B) 10
(C) 24
(D) 32
(E) 120
For this one, if put them on a straight line, the possible arrangements are 5! = 120. However, since it is a circle, you would have: ABCDE = BCDEA = CDEAB = DEABC = EABCD In other word, you count five different linear arrangements which are considered the same in the circular arrangement. 120 / 5 = 24 |
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