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和大家讨论几道数学狗,明天考

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楼主
发表于 2010-12-28 21:59:46 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
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沙发
发表于 2010-12-29 00:28:58 | 只看该作者
Since they ask for minimum, we let institutional investors to buy domestic ONLY.  So institutional investors bought 3/5 of the total.  The rest of the domestic 3/4 - 3/5 = 3/20 would be bought by the individual investors .  

[3/20]/[3/4]=1/5  So individual investors bought at least 1/5 of the domestic trading volumes.

In terms of value, 340 * 3/30 = 51
板凳
发表于 2010-12-29 00:34:18 | 只看该作者
DS: 一个球从斜坡上滚下来,斜坡的长度d与球从坡顶滚到坡地的时间t满足d=t平方。问能否求出球在第一秒内的平均速度和最后一秒内的平均速度之差。
(1)已知坡长25feet
(2)已知总共用了5s
这个我选D


This is simple.  Both conditions are the same since 25= 5^2.

At the end of the first second, d = 1 ft.  So the v1 average = 1/1 = 1 ft/s
At the end of the 4th second, d = 16 ft.  At the end of the 5th second, d = 25 ft.  So during the last second, the ball covers 25-16 = 9 ft.  So the v5 average = 9/1 = 9 ft/s.

The different between the two is 8 ft/s.

Choose D.
地板
发表于 2010-12-29 01:10:34 | 只看该作者
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5#
发表于 2010-12-29 01:48:49 | 只看该作者
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6#
发表于 2010-12-29 02:01:05 | 只看该作者
From the stimulus, you can deduce that B=2*A, C=3*A, D=2*B = 4*A since each segment in-between the adjacent points are equal.

1) A = 2^6, then D = 2^8.  So D is 2^8.  Sufficient.
2) B = 2*9, then D = 2^10. So D is not 2^8. Sufficient.
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