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Sn = a^1 + a^2 + a^3 + . . . + a^n
condition 1) n is odd. If a is even, then a^n ( n = 1, 2, 3, . . ., n) is even, then Sn is even. If a is odd, then a^n ( n = 1, 2, 3, . . ., n) is odd. Since n is odd, Sn is odd.
condition 2) a is odd. Since a is odd, a^n ( n = 1, 2, 3, . . ., n) is odd. In this case, it depends on n. If n is odd, Sn is odd. If n is even, Sn is even.
Combining conditions 1) and 2): Since a is odd, a^n ( n = 1, 2, 3, . . ., n) is odd. Since n is odd, Sn is odd. Sufficient. |
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