Math JJ two problems

fudanwyh · 发表于 2010-11-16 06:27:39

Dont understand this problem at all, can any one help?? thanks a lot!

360. 有7个油桶，其中3个高5米，2个高4米，3个高3米，如果把7个油桶堆成3列，高度最高的那列最不可能是？（又是问possibility的题目。。我又不会做。。选项有9，10，11，12，13

最大的不可能小于平均值。

4087个箱子，分别高5，5，4，4，4，3，3，放到三个vertical的什么里，问最高的那堆有可能的最低高度是多少。我选10

sdcar2010 · 发表于 2010-11-16 06:38:47

If the toppest height is 9, what are the possible arrangement?
Answers: pile 1 : 5, 4; pile 2 : 5, 4; pile 3 : 3, 3, 3. Wait. We still have an extra 5 m tall barrel at hand. Which pile should we put it on? Nowhere without breaking the premise that none of the piles is taller than 9. In fact, even 10 is impossible.

The other way to look at this problem is to calculate the every height for the three piles = (15 + 8 + 9)/3 =10.6. So the tallest pile has to be at least 11 m tall.

fudanwyh · 发表于 2010-11-16 07:13:27

Got you, thanks!

essdella · 发表于 2010-11-16 10:16:21

请问那这里面的第二题呢？我算出来最小不能低于：（10＋12＋9）／3＝10.3,那么最小就应该是11吧？答案是是十么？谢谢！

sdcar2010 · 发表于 2010-11-16 10:20:26

For the second one, the average is (10 + 12 + 6) / 3 = 9.7. So the answer is 10.

essdella · 发表于 2010-11-16 10:28:00

万分感谢！我太马虎了～

Math JJ two problems

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