请教一道余数题

linshigong · 发表于 2010-8-16 22:51:39

这道题不知道怎么做，请牛牛讲解一下思路。
谢谢！

linshigong · 发表于 2010-8-17 20:08:43

没有人知道做么....顶一下

Simon88 · 发表于 2010-8-17 20:13:18

C吧。。。余数应该是29

linshigong · 发表于 2010-8-22 20:26:09

好像不对呃......

jack3939889 · 发表于 2010-8-22 21:20:50

remainder is 5? 29/8=3....5

onetimewolf · 发表于 2010-8-22 21:25:30

http://laiba.tianya.cn/laiba/CommMsgs?cmm=6160&tid=2656613814187023494
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(1)considering 17 = 1X12 + 5 divided by 8 the remainder is 1, 29 = 2X12 + 5 divided by 8 the remainder is 5; so the remainder is not determined. NOT sufficient.
(2)ditto. considering 29 = 1X18 + 11 and 47 = 2X18 + 11. NOT sufficient.
Taken together, and then x = 12m + 5 = 18n + 11; this equation can be satisfied if and only if m = 2, n = 1. Because, consider the geometrical graphs of the two equations, two different lines can intersect in one point at most. so x is determined as 29, and the remainder also be determined.

vivian3209 · 发表于 2010-8-22 22:21:16

http://laiba.tianya.cn/laiba/CommMsgs?cmm=6160&tid=2656613814187023494
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(1)considering 17 = 1X12 + 5 divided by 8 the remainder is 1, 29 = 2X12 + 5 divided by 8 the remainder is 5; so the remainder is not determined. NOT sufficient.
(2)ditto. considering 29 = 1X18 + 11 and 47 = 2X18 + 11. NOT sufficient.
Taken together, and then x = 12m + 5 = 18n + 11; this equation can be satisfied if and only if m = 2, n = 1. Because, consider the geometrical graphs of the two equations, two different lines can intersect in one point at most. so x is determined as 29, and the remainder also be determined.

-- by 会员 onetimewolf (2010/8/22 21:25:30)

65也可以满足1和2，除8余1，所以接着你的分析，应该是选E？

leeyeuktung · 发表于 2010-8-22 22:55:30

同意楼上的,通过这两个条件得出的数,被8除不能够得到唯一的余数,因此选E

linshigong · 发表于 2010-8-23 21:18:05

http://laiba.tianya.cn/laiba/CommMsgs?cmm=6160&tid=2656613814187023494
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(1)considering 17 = 1X12 + 5 divided by 8 the remainder is 1, 29 = 2X12 + 5 divided by 8 the remainder is 5; so the remainder is not determined. NOT sufficient.
(2)ditto. considering 29 = 1X18 + 11 and 47 = 2X18 + 11. NOT sufficient.
Taken together, and then x = 12m + 5 = 18n + 11; this equation can be satisfied if and only if m = 2, n = 1. Because, consider the geometrical graphs of the two equations, two different lines can intersect in one point at most. so x is determined as 29, and the remainder also be determined.

-- by 会员 onetimewolf (2010/8/22 21:25:30)

65也可以满足1和2，除8余1，所以接着你的分析，应该是选E？

-- by 会员 vivian3209 (2010/8/22 22:21:16)

确实29、65都满足(1)和(2)，答案是E

可是我看上面那位的分析也没错啊，x = 12m + 5 = 18n + 11确实是2条直线，应该只有1个交点，但为啥能得出2个X?

linshigong · 发表于 2010-8-23 23:30:18

http://laiba.tianya.cn/laiba/CommMsgs?cmm=6160&tid=2656613814187023494
--------------------------------------------------------------------------------------------------------
(1)considering 17 = 1X12 + 5 divided by 8 the remainder is 1, 29 = 2X12 + 5 divided by 8 the remainder is 5; so the remainder is not determined. NOT sufficient.
(2)ditto. considering 29 = 1X18 + 11 and 47 = 2X18 + 11. NOT sufficient.
Taken together, and then x = 12m + 5 = 18n + 11; this equation can be satisfied if and only if m = 2, n = 1. Because, consider the geometrical graphs of the two equations, two different lines can intersect in one point at most. so x is determined as 29, and the remainder also be determined.

-- by 会员 onetimewolf (2010/8/22 21:25:30)

65也可以满足1和2，除8余1，所以接着你的分析，应该是选E？

-- by 会员 vivian3209 (2010/8/22 22:21:16)

确实29、65都满足(1)和(2)，答案是E

可是我看上面那位的分析也没错啊，x = 12m + 5 = 18n + 11确实是2条直线，应该只有1个交点，但为啥能得出2个X?

-- by 会员 linshigong (2010/8/23 21:18:05)

想通了上面这个，其实交不交点没有意义了。

但这道题除了把29、65代进去算以外，有没有别的方法或者思路呢？

请教一道余数题

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