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楼主
发表于 2010-7-15 13:12:47 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
If x and y are positive integers such that x=8y+12, what is the greatest common disisor of x and y?
(1) x=12u, where u is an integer.
(2) y=12z, where z is an integer.
答案给的是B
我选的是E.
请帮我看一下,谢谢。
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沙发
 楼主| 发表于 2010-7-16 12:14:32 | 只看该作者
can anyone helpme?
thank you very much!
板凳
 楼主| 发表于 2010-7-16 12:43:26 | 只看该作者
93. the lifetimes of all the batteries produced by a certain company in a year have a distribution that is symmetric about the mean m. if the distribution has a standard deviation of d, what percent of the distribution is greater than m+d?
(1)68 percent of the distribution lies in the interval from m-d to m+d, inclusive.
(2)16 percent of the distribution lis less than m-d
答案是D
为什么呢?
麻烦大家帮我看看
谢谢。
地板
 楼主| 发表于 2010-7-17 18:58:10 | 只看该作者
can anyone help me?
5#
发表于 2010-7-17 19:16:50 | 只看该作者
If x and y are positive integers such that x=8y+12, what is the greatest common disisor of x and y?
(1) x=12u, where u is an integer.
(2) y=12z, where z is an integer.
答案给的是B
我选的是E.
请帮我看一下,谢谢。
-- by 会员 meckychen (2010/7/15 13:12:47)




1.      x=12u,   means   12u=8y+12 ,   means 12u=8y-u
insufficient ,,  because  x is divisible by 12 and u  while   y is divisible by u-1 and 12/8

2.     y=12z,  means    x=12z+12, means x=12括号z+1括号完毕
when z is a integer,  z+1 is a integer   ,   so   y and x  are all divisible by 12.

since z and 括号z+1括号完毕share no factor other than 1, so the greatest common divisor should be 12



B


soli ,sth wrong with my keyboard
6#
发表于 2010-7-17 19:21:35 | 只看该作者
93. the lifetimes of all the batteries produced by a certain company in a year have a distribution that is symmetric about the mean m. if the distribution has a standard deviation of d, what percent of the distribution is greater than m+d?
(1)68 percent of the distribution lies in the interval from m-d to m+d, inclusive.
(2)16 percent of the distribution lis less than m-d
答案是D
为什么呢?
麻烦大家帮我看看
谢谢。
-- by 会员 meckychen (2010/7/16 12:43:26)



对称分布,你可以画一个x轴,中值为m,      
标准差为d,其实可以不用管,

问的是离差大于d的部分,也就是说m的两边都得算,大于m+d和小于m-d的都属于要求的部分

1.   给了内部的部分
2.   给了外部的部分两边中的一边,但是由于图形是对称的,所以其实把这个数x2就是离差大于d的部分了
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