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suppose the cars are marked sepertely as A, B, and C. The first time, the guy will take any car. Set the car number is A. The second time, he will have 3 choices: A, B and C. In order to take a different car. He has to chose B or C. The probablity is 2/3. The third time, he still have 3 choces. However, he has only one choice -- the car he didn't take in the first and second time. The prabability is 1/3. 2/3*1/3=2/9 |