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题目分享:)不大会哦~请大牛指点

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楼主
发表于 2008-9-7 14:41:00 | 只看该作者

题目分享:)不大会哦~请大牛指点

h(n) is defined to be the product of all the even integers from 2 to n, inclusive. if P is smallest prime factor of

h(100)+1,then P is:

A between 2 and 10

E greater than 40

 the answer is E

but I can't understand

help~~~~~~~~~~

沙发
发表于 2008-9-7 16:45:00 | 只看该作者
h(100)=2*4*6...100=2(1*2*3*4...50) so,2,3,4,5...47,48,49,50,all of them are the factor of h(100),and they definitely can not be the factor of h(100)+1 because two consecutive integer have no common factor.
板凳
发表于 2008-9-7 17:07:00 | 只看该作者
以下是引用wxy831在2008-9-7 16:45:00的发言:
 two consecutive integer have no common factor.

oh,my!

thx

地板
发表于 2008-9-7 19:40:00 | 只看该作者
太强了
5#
发表于 2008-9-8 00:49:00 | 只看该作者

路过,只是没有明白???

6#
发表于 2008-9-8 00:50:00 | 只看该作者

谢谢2楼的解答:h(100)=2*4*6...100=2(1*2*3*4...50) so,2,3,4,5...47,48,49,50,all of them are the factor of h(100),and they definitely can not be the factor of h(100)+1 because two consecutive integer have no common factor.

请问:按这个意思“two consecutive integer have no common factor.”,

 smallest prime factor of

h(100)+1 大于50 是吗?

先谢谢了!

7#
发表于 2008-9-8 06:55:00 | 只看该作者
co-ask
8#
发表于 2008-9-8 10:04:00 | 只看该作者
应该是2^(n/2)*(1*2*3*...*50)吧?
9#
发表于 2008-9-8 10:10:00 | 只看该作者

LS理解有误,提取了个2而已,不涉及乘方

大于50  大于40的选项有点玄妙哦

10#
发表于 2008-9-8 11:39:00 | 只看该作者
以下是引用梵尘在2008-9-8 0:50:00的发言:

谢谢2楼的解答:h(100)=2*4*6...100=2(1*2*3*4...50) so,2,3,4,5...47,48,49,50,all of them are the factor of h(100),and they definitely can not be the factor of h(100)+1 because two consecutive integer have no common factor.

请问:按这个意思“two consecutive integer have no common factor.”,

 smallest prime factor of

h(100)+1 大于50 是吗?

先谢谢了!

Just acquire how to consider, answer is not important
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