h(100)=2*4*6...100=2(1*2*3*4...50) so,2,3,4,5...47,48,49,50,all of them are the factor of h(100),and they definitely can not be the factor of h(100)+1 because two consecutive integer have no common factor.
谢谢2楼的解答:h(100)=2*4*6...100=2(1*2*3*4...50) so,2,3,4,5...47,48,49,50,all of them are the factor of h(100),and they definitely can not be the factor of h(100)+1 because two consecutive integer have no common factor.
请问:按这个意思“two consecutive integer have no common factor.”,
谢谢2楼的解答:h(100)=2*4*6...100=2(1*2*3*4...50) so,2,3,4,5...47,48,49,50,all of them are the factor of h(100),and they definitely can not be the factor of h(100)+1 because two consecutive integer have no common factor.
请问:按这个意思“two consecutive integer have no common factor.”,
smallest prime factor of
h(100)+1 大于50 是吗?
先谢谢了!
Just acquire how to consider, answer is not important