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LSAT-1-4-19

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楼主
发表于 2004-4-29 12:25:00 | 只看该作者

LSAT-1-4-19

L1-4-19
There are at least three people in the room. At most two people in the room recognize each other. At least one person in the room recognizes everybody else in the room.
Which one of the following is NOT consistent with the above?
(A) Four people are in the room.
(B) No two people in the room recognize each other.
(C) At most one person in the room recognizes everybody else in the room.
(D) Anyone in the room who recognizes any other person in the room is also recognized by that person.
(E) Two people in the room recognize every one else in the room.
说实话,这道题目我看了好几遍了,始终也猜不透,请斑竹一定帮忙!
沙发
发表于 2004-4-29 13:25:00 | 只看该作者

Sorry, 越斑竹代挨砖...

Suppose there are 3 people, A, B and C. Assume that A knows B and C (At least one person in the room recognizes everybody else in the room), note: A-->B and A-->C; then if D is OK, A<-->B, A<-->C, so there are 3 people knows each other which does not confirm with "At most two people in the room recognize each other", so D is not correct.

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