ChaseDream
搜索
12
返回列表 发新帖
楼主: jikuren
打印 上一主题 下一主题

[讨论]3月JJ-131

[复制链接]
11#
发表于 2009-3-11 13:10:00 | 只看该作者

同意14

12#
发表于 2009-3-11 13:44:00 | 只看该作者

133.(PS)X35
   
1  x+y35整除  y最小值可以是多少
    

  选项有  4 14 什么的

是否是14啊?x 可以表示成 15a+1 要被15整除至少加14

assume that y is positive, then 14 is right

the general expression for y is .....-16,-1,14,29,44,59, with an increment of 15

 
13#
发表于 2009-3-11 13:50:00 | 只看该作者

131.(DS)22 students 给他们发pencil 每人至少一支
   

   
会不会有两个人拿的pencil数是一样的
    

  (1)每人少于22   (2)总共250

(1): not sufficient

could have 2 people with same number (ex: 7 pencils)
or everyone has different numbers since there is no limit on the total numbers of pencils

(2): 1+2+.......+21=126
250-126=124; so 22 people each has different numbers of pencils

or 1+2+.........20+20=125
250-125=125
two people have the same number of pencils

so 2 is not right

1+2: consider the first 21 students, if each of them has different numbers of pencils, then the total numbers for them would be 1+.....+21=126, because any number before 22 can be counted once, then the 22th student must have 124 pencils, but it is against condition (1). Then it means that my assumption that each of the 21 students has different numbers of pencils is false.

So the answer is C
您需要登录后才可以回帖 登录 | 立即注册

Mark一下! 看一下! 顶楼主! 感谢分享! 快速回复:

手机版|ChaseDream|GMT+8, 2025-10-4 17:54
京公网安备11010202008513号 京ICP证101109号 京ICP备12012021号

ChaseDream 论坛

© 2003-2025 ChaseDream.com. All Rights Reserved.

返回顶部