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[求助]GG10的第15题不会做,大家帮帮我

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楼主
发表于 2008-12-23 09:44:00 | 只看该作者

[求助]GG10的第15题不会做,大家帮帮我

题目:Which of the following equations has a root in common with X2– 6X + 5 = 0?

(A) X2
            
+ 1 = 0

(B) X2x – 2 =0

(C) X2– 10x – 5 =0

(D) 2 X2– 2 =0

(E) X2– 2x – 3 =0

解释:

Since X2
                    
– 6X + 5 = (X - 5)(X- 1), the roots

of X2– 6X + 5 = 0 are 1 and 5. when

these two values are substituted in each

of the five choices to determine

whether or not they satisfy the equation,

only in D does a value satisfy the

equation, namely, 2(1) 2
                    
– 2 = 0. So, D

is the correct answer.

看完解释,还是不明白X2
                    
– 6X + 5 为什么会等于 (X - 5)(X- 1)阿?各位牛牛帮帮我

Since X2
        
– 6X + 5 = (X - 5)(X- 1), the roots

of X2– 6X + 5 = 0 are 1 and 5. when

these two values are substituted in each

of the five choices to determine

whether or not they satisfy the equation,

only in D does a value satisfy the

equation, namely, 2(1) 2
        
– 2 = 0. So, D

is the correct answer.

看完解释,还是不明白X2
        
– 6X + 5 为什么会等于 (X - 5)(X- 1)阿?各位牛牛帮帮我

沙发
发表于 2008-12-23 09:54:00 | 只看该作者

这个是最简单的因式分解啊。。。

这个最好去看看教材吧。。。

板凳
 楼主| 发表于 2008-12-23 12:06:00 | 只看该作者

这是题目:Which of the following equations has a root in common with X2– 6X + 5 = 0?

可是题目中没给出任何条件是X2– 6X + 5 = (X-1)(X-5)。

题目遗漏了

地板
发表于 2008-12-23 13:51:00 | 只看该作者
不是遗漏了,通过X2– 6X + 5 =0推出 (X-1)(X-5)=0,这是数学上最基本的因式分解,自己可以推出的
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