题目:Which of the following equations has a root in common with X2– 6X + 5 = 0? (A) X2 + 1 = 0 (B) X2– x – 2 =0 (C) X2– 10x – 5 =0 (D) 2 X2– 2 =0 (E) X2– 2x – 3 =0
解释:Since X2 – 6X + 5 = (X - 5)(X- 1), the roots of X2– 6X + 5 = 0 are 1 and 5. when these two values are substituted in each of the five choices to determine whether or not they satisfy the equation, only in D does a value satisfy the equation, namely, 2(1) 2 – 2 = 0. So, D is the correct answer. 看完解释,还是不明白X2 – 6X + 5 为什么会等于 (X - 5)(X- 1)阿?各位牛牛帮帮我 Since X2 – 6X + 5 = (X - 5)(X- 1), the roots of X2– 6X + 5 = 0 are 1 and 5. when these two values are substituted in each of the five choices to determine whether or not they satisfy the equation, only in D does a value satisfy the equation, namely, 2(1) 2 – 2 = 0. So, D is the correct answer. 看完解释,还是不明白X2 – 6X + 5 为什么会等于 (X - 5)(X- 1)阿?各位牛牛帮帮我 |