I think you missed some important info in the original question.
13. A certain basketball team that has played 2/3 ATH extrusionok="f" gradientshapeok="t" connecttype="rect">ATH>of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
1). The total number of its games=(17+3)/(2/3)=30 2). The number of its remaining games=30-20=10 3). Let "the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games" be X.
Then: (17+10-x)/30>3/4---> x=4 |