请教og13 problem solving 196审题问题

kaye523

求教og 13 problem solving 196 题 From the consecutive integers -10 to 10, inclusive, 20 integers are randomly chosen with repitions allowed.What is the least possible value of the product of the 20 integers? A (-10)^20 B (-10)^10 C 0 D -(10)^19 E -(10)^20 Answer: If -10 is chosen an odd number of times and 10 is chosen the remaining number of times (for example, choose -10 once and choose 10 nineteen times, or choose -10 three times and choose 10 seventeen times), then the product of the 20 chosen numbers will be -(10)^20.Note that -(10)^20 is less than -(10)^19,the only other negative value among the answer choices. the correct answer is E

先谢谢回答的人啦
这道题的计算我明白，但我把“the least possible value”理解成“最不可能出现的值”也就是概率最小的值了
想问下大家题中的表达是否存在这种歧义？如果题目要问“最不possible的值”会用怎样的问法呢？
再次感谢！

kaye523

阿普阿普阿普~

kaye523

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