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请教 lsat12,sec1,4 & 12

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楼主
发表于 2004-11-27 22:59:00 | 只看该作者

请教 lsat12,sec1,4 & 12

,4. If the regulation of computer networks is to be modeled on past legislation, then its model must be either legislation regulating a telephone system or else legislation regulating a public broadcasting service. If the telephone model is used, computer networks will be held responsible only for ensuring that messages get transmitted. If the public broadcast model is used, computer networks will additionally be responsible for the content of those messages. Yet a computer network serves both these sorts of functions: it can serve as a private message service or as a publicly accessible information service. Thus neither of these models can be appropriate for computer networks.


The passage is structured to lead to which one of the following conclusions? (A) Regulation of computer networks is required in order to ensure the privacy of the messages transmitted through such networks. (B) The regulation of computer networks should not be modeled on any single piece of past legislation. (C) Computer networks were developed by being modeled on both telephone systems and television networks. (D) Legislators who do not have extensive experience with computers should not attempt to write legislation regulating computer networks. (E) A computer network merely duplicates the functions of a telephone systems and a television system.


这道题我看不明白。特别到了黑体字部分,有人帮我解释一下么? 谢谢。还有正确选项b的past


leguslation在原文没有所指阿


[此贴子已经被作者于2004-11-27 23:17:30编辑过]
沙发
 楼主| 发表于 2004-11-27 23:17:00 | 只看该作者

12. In the Centerville Botanical Gardens, all tulip trees are older than any maples. A majority, but not all, of the garden's sycamores are older than any of its maples. All the garden's maples are older than any of its dogwoods.

If the statements above are true, which one of the following must also be true of trees in the Centerville Botanical Gardens? (A) Some dogwoods are as old as the youngest tulip trees. (B) Some dogwoods are as old as the youngest sycamores.
(C) Some sycamores are not as old as the oldest dogwoods. (D) Some tulip trees are not as old as the oldest sycamores. (E) Some sycamores are not as old as the youngest tulip trees.

答案e,但是我认为c也是对的。 应该是 T〉M〉D

some S〉M,so,some S 一定不等于D 。

请大家帮我看看                 

板凳
发表于 2004-11-28 00:41:00 | 只看该作者
4。原文讨论的是计算机网络的立法要以什麽为版本。原文说立法版本必须限于telephone system 和 legislation regulating a public broadcasting service。每种立法版本各有特点。但(YET)计算机网络必须具备这两种立法版本的特点,不能只具备其中一种立法版本的特点。其实B就是原文结论THUS后那句话的另一种说法。PAST LEGISTRATION就是指原文的那两种立法版本。注意原文第一句话提到。
地板
发表于 2004-11-28 00:59:00 | 只看该作者

12题,本来画图最清楚。这里无法画图。

原文有两个大小关系:T>M。多数S>M>D。注意不包括等于。C的情况是可能,不是MUST BE。而E是MUST BE (必须)。由于所以T比M老,即最YONG的T也比最老的M老。而肯定有一些S比最老的M还YONG(majority)。所以肯定(must be)有一些S比最YONG的T年轻。即E

5#
 楼主| 发表于 2004-11-28 19:07:00 | 只看该作者

c : Some sycamores are not as old as the oldest dogwoods.

lawyer_1 谢谢你的耐心解答,第一个体明白了,第二个体:还要请你看看。

既然说有些s大于m那么这些s一定大于d,那么我们说some s 不等于最老的d应该是mustbe正确的选项阿。难道不是吗?? 继续牛角尖中~~

6#
发表于 2004-11-28 21:46:00 | 只看该作者

1。这虽和原文答案关系不大,但逻辑要区分不同概念。原文的S是majority(51-100),多数,不是some(1-100),有一些。


2。我举个例子:S多数是1000-1200年的,少数是700-800年的。M都是都是800-900年的,D都是500-600年的。这种情况满足了多数S>M>D.但是所有S都老于D。不存在比最老的D年轻的问题。你会不会对C理解错了。C的意思为:有一些S比最老的D年轻或一样大。


[此贴子已经被作者于2004-11-28 21:54:20编辑过]
7#
 楼主| 发表于 2004-11-28 21:56:00 | 只看该作者

c : Some sycamores are not as old as the oldest dogwoods

我照直翻译:有些s 的年龄不等于那个最老的d。

我明白了,但是这句话真的有点歧义。 再次谢谢lawyer同学

8#
发表于 2019-8-10 15:40:04 | 只看该作者
entia 发表于 2004-11-27 22:59
,4. If the regulation of computer networks is to be modeled on past legislation, then its model mus ...

Spot the question type: Main point

If reg is to be modeled on past legislation ---> either regulation on telephone system or regulation on public broadcasting services.

No tel or No public bs ---> Regulation is " not to " be modeled on past legislation

If telephone model is used ---> CN will be responsible ---> ensuring the messages get transmitted.

If the public broadcast model is used ---> CN will be responsible also for the content of the messages.

CN serves both functions = 1. private message services or 2. publicly accessible information services

C: Tel + Public BS ---> No appropriate for CN  ( Appropriate for CN ---> No Tel or No Public ps )

So, Appropriate for CN ---> No tel or No public ps ---> regulation is not to be modeled

Appropriate for CN ---> Not to be responsible for ensuring messages get transmitted ---> no tel

Appropriate for CN ---> Not to be responsible for the content of the services ---> no public bs

*The logic chains shows really clear that if models can be appropriate for CN, regulation must not be modeled.

If computer network legislation modeled on past legislation, then either use 1) telephone legislation (resp. only for transmission) or 2) public broadcasting service legislation (resp. also for content).

Computer network serves both functions (private message or public information).

Neither legislative model is appropriate.
The first statement tells us that if we're going to model past legislation, we only have two options (telephone and public broadcast legislation). The last statement tells us that neither of those options is appropriate. That leaves us with exactly zero possible pieces of past legislation on which to model the planned legislation, which is essentially what (B) says.

Consider this analogy:
If you want to get the lunch special, you must order either the Reuben or the pastrami. But you are allergic to pastrami, and find Reuben sandwiches horrific. Therefore, neither are appropriate lunch choices for you.

What can we conclude? You ain't getting the lunch special.

You may both have overlooked that the first sentence limits the possible options to the two models.



let us check the answers.

A. If ensure the privacy of messages transmitted though the networks, it must be true that the regulation of CN is required. ( New concept ! we have not discussed anything relevant to the privacy )

B. Correct answers.

C. not necessary to be true

D. not relevant

E. not relevant
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