[原始] 伍月肆日原始寂静汇总（共546只 更新至06/03 ）---结贴

泾渭不凡

[attachimg=65,71]101091[/attachimg][attachimg=65,71]101091[/attachimg][attachimg=65,71]101091[/attachimg][attachimg=65,71]101091[/attachimg]

Leonyc

Leonyc

Time for bed!

泾渭不凡

-- by 会员 Leonyc (2012/5/24 1:47:03)

泾渭不凡

Time for bed!

-- by 会员 Leonyc (2012/5/24 1:47:37)

(*^__^*) 嘻嘻……~~~
[attachimg=136,136]101104[/attachimg]夜猫小饭呦~~~哎哎哎啊肿么办~~~~谢谢leo亲来看饭饭酱~~！

Leonyc

Time for bed!

-- by 会员 Leonyc (2012/5/24 1:47:37)

(*^__^*) 嘻嘻……~~~
101104夜猫小饭呦~~~哎哎哎啊肿么办~~~~谢谢leo亲来看饭饭酱~~！

-- by 会员 泾渭不凡 (2012/5/24 9:15:55)

逛夜猫版块是例行事务，哈哈
我躺了......

kimchilan

从来没有post过。。。如果Post错了 请帮我转一转？

I came across this question...

how many sets of two points in 3-dimensional space can have a distance of 5sqrt3?
A. 0
B. 1
C. 5
D. 8
E. more than 8 (A-D 具体数字不清楚。。。E应该是对的）

思路（不知道对不对）： 5sqrt3 = sqrt of 75, distance between two points in 3D = sqrt [(x2-x1)^2+(y2-y1)^2+(z2-z1)^2] this means that 75 should be made up of three squares, which would be 49, 25, and 1. to get 49, 25, and 1, (x2-x1) or (y2-y1) or (z2-z1) could be either 9/-9, 5/-5, or 1/-1...given all these possibilities, there should be more than 8 sets???

泾渭不凡

从来没有post过。。。如果Post错了 请帮我转一转？

I came across this question...

how many sets of two points in 3-dimensional space can have a distance of 5sqrt3?
A. 0
B. 1
C. 5
D. 8
E. more than 8 (A-D 具体数字不清楚。。。E应该是对的）

思路（不知道对不对）： 5sqrt3 = sqrt of 75, distance between two points in 3D = sqrt [(x2-x1)^2+(y2-y1)^2+(z2-z1)^2] this means that 75 should be made up of three squares, which would be 49, 25, and 1. to get 49, 25, and 1, (x2-x1) or (y2-y1) or (z2-z1) could be either 9/-9, 5/-5, or 1/-1...given all these possibilities, there should be more than 8 sets???

-- by 会员 kimchilan (2012/5/24 13:11:13)

谢谢亲，小饭已经替亲开贴了~~要是亲还能想起什么的话~~^^，去跟帖就好了~~谢谢哈~~辛苦~~祝好
链接：http://forum.chasedream.com/GMAT_Math/thread-720369-1-1.html

泾渭不凡

泾渭不凡