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楼主
发表于 2012-3-14 12:36:34 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
gwd第一套中的,if 10的50次方-74 is written as an integer in base 10 notation,what is the sum of the digits in that interger。答案有 424  433 440 449 467.   大家能帮忙解释一下题干吗?

还有一道题,Running at their respective constant rates,machine X takes 2 days longer to produce w widgets than machine Y。At these rates ,if the two machines  together produce 5/4w widgets in 3 days,how many days would it take  machine X alone to produce 2w widgets。答案有4 6 8 10 12.
 感觉好绕,没弄清楚意思,希望大家帮帮忙
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沙发
发表于 2012-3-14 12:39:36 | 只看该作者
100-74=26
1000-74=926
10000-74=9926
100000-74=99926
...
....
10^52-74=......26

"what is the sum of the digits in that interger"
9+9+9+...+2+6

謝謝!
板凳
发表于 2012-3-14 12:40:17 | 只看该作者
100-74=26
1000-74=926
10000-74=9926
100000-74=99926
...
....
10^52-74=......26

"what is the sum of the digits in that interger"
9+9+9+...+2+6

謝謝!
-- by 会员 treewing929 (2012/3/14 12:39:36)


10^50-74=......26
地板
发表于 2012-3-14 12:44:38 | 只看该作者
gwd第一套中的,if 10的50次方-74 is written as an integer in base 10 notation,what is the sum of the digits in that interger。答案有 424  433 440 449 467.   大家能帮忙解释一下题干吗?

还有一道题,Running at their respective constant rates,machine X takes 2 days longer to produce w widgets than machine Y。At these rates ,if the two machines  together produce 5/4w widgets in 3 days,how many days would it take  machine X alone to produce 2w widgets。答案有4 6 8 10 12.
 感觉好绕,没弄清楚意思,希望大家帮帮忙
-- by 会员 kearywu (2012/3/14 12:36:34)


第二條
time=quantity/rate
ratex=x, ratey=y

let quantity = 1
timex-timey=2

together=ratex+ratey
quantity=(5/4)*w
time=3

還沒有驗算
謝謝!
5#
 楼主| 发表于 2012-3-14 20:43:50 | 只看该作者
可是,木有3这个答案啊……求再看看
6#
发表于 2012-3-14 20:45:55 | 只看该作者
可是,木有3这个答案啊……求再看看
-- by 会员 kearywu (2012/3/14 20:43:50)


我不是說答案是 3....

題目說 3 days
7#
发表于 2012-3-14 20:53:05 | 只看该作者
gwd第一套中的,if 10的50次方-74 is written as an integer in base 10 notation,what is the sum of the digits in that interger。答案有 424  433 440 449 467.   大家能帮忙解释一下题干吗?

还有一道题,Running at their respective constant rates,machine X takes 2 days longer to produce w widgets than machine Y。At these rates ,if the two machines  together produce 5/4w widgets in 3 days,how many days would it take  machine X alone to produce 2w widgets。答案有4 6 8 10 12.
 感觉好绕,没弄清楚意思,希望大家帮帮忙
-- by 会员 kearywu (2012/3/14 12:36:34)


答案是 12 嗎?
8#
发表于 2012-3-14 20:55:41 | 只看该作者
問題: 2W/Rx=?

(1) W/Rx - W/Ry = 2
(2) (5/4*W)/(Rx+Ry) = 3
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