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楼主
发表于 2012-1-11 11:57:16 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
4个数s, t, u, v,下面哪组数的standard deviation跟它们一样?(s,t,u,v 就是字母,不是实际数)
1. |s|, |t|, |u|. |v|
2. 3s, 3t, 3u, 3v
3. s^3, t^3, u^3, v^3
4. 2s+2, 2t+2, 2u+2, 2v+2

1.2.4 应该不对,3?
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沙发
发表于 2012-1-11 11:58:03 | 只看该作者
3也不对
板凳
发表于 2012-1-11 12:01:50 | 只看该作者
I just posted in other thread, "standard deviation is basically the difference between each number. Say s t u v = 1, 2, 3, 4, the gap between each number is 1. If 3s, 3t, 3u, 3v, then 3, 6, 9, 12 and gap between each number increased to 3.  The correct answer for number 4 is (|s|, |t|, |u|, |v|). Multiplication will increase the standard deviation "
地板
 楼主| 发表于 2012-1-11 12:04:58 | 只看该作者
绝对值那个啊?那如果数字有负的,绝对值不是把差距缩小了啊?
5#
发表于 2012-1-11 12:07:15 | 只看该作者
the absolute value doesn't matter, what matters for standard deviation is the difference between each number. if s t u v is -1, -2, -3, -4, the difference between each number is still 1. Changing them to |s|, |t|, |u|, |v|, then the difference between 1, 2, 3, 4 is still 1.
6#
发表于 2012-1-11 12:10:06 | 只看该作者
eeks you are right, i didnt consider two positive and two negatives. is this all the problem gave us?
7#
发表于 2012-1-11 12:11:16 | 只看该作者
同求 up
8#
发表于 2012-1-11 12:11:25 | 只看该作者
I don't see why number 3 can be correct since the number 1^3 is still one.. maybe the right answer is none of them
9#
发表于 2012-1-11 13:31:29 | 只看该作者
4个都不对
1、绝对值,会改变密度分布
2、3倍,则D也为3倍
3、3次方,就跟不对了,同样改变密度分布
4、2倍再加2,同2~~~
除非他给出具体的限定,不然这几个都不对
10#
发表于 2012-1-11 19:26:04 | 只看该作者
我也觉得都不对 ><
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