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This is akin to do the following: 1) put one letter into its corresponding evelope. 2) put the othe three letters into evelopes. Total possibilites are 6: 1 2 3 A B C A C B B A C B C A C A B C B A 3) caculate what is the probability that all the othe three letters are in wrong evelopes. Only C A B; B C A fulfil this requirement assuming A, B, C matches with 1, 2,3, respectively.
2/6 = 1/3 |
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