(1) Unit digit of (3^x + 1) = 3^(4n+2) + 1 = (81)^n * 9 + 1 = 9+1 = 0 So remainder is zero, SUFFICIENT (2)x> 4 , if x =5 Unit digit of (3^5 + 1) = 3 + 1 =4 So remainder is 4 if x = 6 Unit digit of (3^6+ 1) = 9 + 1 = 0 So remainder is 0. INSUFFCIENT Hence A.