药饵叁灵 献坐稳狗

AlohaDJ

Keep fighting till the victory!

-- by 会员 sdcar2010 (2010/12/30 22:17:53)

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THKS NN! Thanks a lot for you help in maths!!

sdcar2010

Another possible way of delivering the question:
What is the greatest number for n such that 2^n divides 2! x 8! ?

2! x 8! = 2 x 2^3 x 7 x 2 x 3 x 5 x 2^2 x 3 x 2 = 2^8 m

So the greatest value for n is 8 for 2^n devides 2! x 8!