因子的公式?

lbccd

呃 就是说有没有算1个数有多少因子的公式呢....

比如12    1 2 3 4 6 12   共6个..要是数大了有公式能算么..

lbccd

我...

田田叶子

没有

lbccd

啊...那就1个1个掰手指头算呐...

gmatbenben

There is a formula.

If N=(A^j)*(B^k)*(C^m)*(D^n), then
the number of factors of N is equal to: (j+1)*(k+1)*(m+1)*(n+1)

Example:
Since 180 = (2^2)*(3^2)*(5^1),
180 has (2+1)*(2+1)*(1+1)=18 factors.

lbccd

There is a formula.

If N=(A^j)*(B^k)*(C^m)*(D^n), then
the number of factors of N is equal to: (j+1)*(k+1)*(m+1)*(n+1)

Example:
Since 180 = (2^2)*(3^2)*(5^1),
180 has (2+1)*(2+1)*(1+1)=18 factors.

-- by 会员 gmatbenben (2010/12/24 14:04:20)

谢谢啦~ 不愧是大nn呢~ 栖栖凌少给你啦~

hyu3

嗯，谢啦！