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3:A certain meter records voltage between 0 volts and 10 volts, inclusive. If the average( arithmetic mean) value of 3 recordings on the meter was 8 volts, what was the smallest possible recording, in volts?
The total of volts for the 3 recordings = a + b + c = 3*8 = 24 In order to get the smallest possible recording, you need to force the other 2 recordings at the maximum value, which is 10 in our case. So remove the two 10's from 24, you got 4 volts as the smallest possible recording. |
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