well, the problem is that you don't care whether xyz > 0; the problem asks for x(y + z) > 0, since we know that x, y, and z all have the same sign, that means y + z have the same sign as x thus x * (y + z) > 0
以下是引用tiger1234在2004-9-19 9:37:00的发言: well, the problem is that you don't care whether xyz > 0; the problem asks for x(y + z) > 0, since we know that x, y, and z all have the same sign, that means y + z have the same sign as x thus x * (y + z) > 0
well if xy > 0 and yz > 0 => xy * yz > 0 = x * y^2 * z > 0 since y^2 > 0 => x*z > 0 thus x and z have the same sign as well, since x and y have the same sign, y and z have the same sign, and x and z have the same sign, thus x, y, z all have the same sign
以下是引用tiger1234在2004-9-19 11:09:00的发言: well if xy > 0 and yz > 0 => xy * yz > 0 = x * y^2 * z > 0 since y^2 > 0 => x*z > 0 thus x and z have the same sign as well, since x and y have the same sign, y and z have the same sign, and x and z have the same sign, thus x, y, z all have the same sign