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[求助]gwd12-14

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楼主
发表于 2009-4-5 14:43:00 | 只看该作者

[求助]gwd12-14

Q14:

Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length, The length of each red stick is 18 inches less than the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average(arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?

答案是 24,可是我怎么觉得少条件呢?

求助,谢谢!

沙发
发表于 2009-4-5 14:53:00 | 只看该作者
以下是引用TASSEL在2009-4-5 14:43:00的发言:

Q14:

Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length, The length of each red stick is 18 inches less than the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average(arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?

答案是 24,可是我怎么觉得少条件呢?

求助,谢谢!

不少条件,就是比较绕,很容易让人去想每个box里stick的数量,其实没关系

首先定义:

length of each red stick = R

the average length of the sticks in Box W = W

the average length of the sticks in Box V = V

题目给的条件:

W-R=18

R-V=6

求解:W-V=(W-R)+(R-V)=18+6=24

抛砖引玉……

板凳
 楼主| 发表于 2009-4-5 15:22:00 | 只看该作者

谢谢楼上

我看了好几遍,居然都搞错了,把the length of the sticks in Box W,V 误认为是 the length of the blue sticks in Box W,V.

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