(1) actually b(100)-1 is divisible by 5 => last digit is 0 or 5.=> b(99)-1 last digit is 0 or 5. so it's difficult to say it's divisible by 2. hence, can't conclude divisible by 10.
(2) b(1)=-1 can conclude that b(99)-1= -1+98*5-1 can't be divisible by 10.
(1) actually b(100)-1 is divisible by 5 => last digit is 0 or 5.=> b(99)-1 last digit is 0 or 5. so it's difficult to say it's divisible by 2. hence, can't conclude divisible by 10.
(2) b(1)=-1 can conclude that b(99)-1= -1+98*5-1 can't be divisible by 10.