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[求助]还是prep数学DS的一些题不太明白,请教各位NNs了!

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楼主
发表于 2009-1-6 22:53:00 | 只看该作者

[求助]还是prep数学DS的一些题不太明白,请教各位NNs了!

prep数学-DS2:

#197:

The integers m and p are such that 2 < m < p and m is not a factor of p. If r is the remainder when p is divided by m, is r > 1 ?

(1) The greatest common factor of m and p is 2.

 (2) The least common multiple of m and p is 30.

答案是A,我选D--按条件2给出信息:P&M又最小公倍数为30,又根据题干,2 < m < p 且其中一个不是另一个的因子,只有5&6; 3&10, 折两组相除余数=1,否定回答了问题,这样条件2也就充分了啊。

#184:

If k is an integer greater than 1, is k equal to 2的r次方 for some positive integer r ?

(1) k is divisible by 2的6次方.

(2) k is not divisible by any odd integer greater than 1.

答案是B,我选D--不明白为是么条件1不行啊?能被2的6次方整除的书难道不能被2的r次方整除么?

#129:

If t is a positive integer and r is the remainder when t² + 5t + 6 is divided by 7, what is the value of r ?

(1) When t is divided by 7, the remainder is 6.

(2) When t² is divided by 7, the remainder is 1.

答案是A,我选C,这道题不明白

#117:

What is the remainder when the positive integer n is divided by the positive integer k, where k > 1 ?

(1) n = (k + 1)^3

(2) k = 5

答案是A,我选C

#93:

The lifetimes of all the batteries produced by a certain company in a year have a distribution that is symmetric about the mean m. If the distribution has a standard deviation of d, what percent of the distribution is greater than m + d ?

(1) 68 percent of the distribution lies in the interval from m - d to m + d, inclusive.

(2) 16 percent of the distribution is less than m - d.

答案是D,我选C, 这个答案真觉得有些不对啊

#54:

If y is an integer and y = |x | + x, is y = 0 ?

(1) x < 0

(2) y < 1

答案是D,我选A, 条件2怎能充分呢?如果X=1/3不就不成立

沙发
发表于 2009-1-6 23:10:00 | 只看该作者

#54: y is an integer

#93:答案是D.

(1)m 为 m - d 和m + d的中点.故m到m + d为68%/2=34%,然后所问为50-34=16%;

(2)m - d到m为50-16=34%,而m 为 m - d 和m + d的中点,因此m到m + d为34%,然后所问为50-34=16%.

所以选D.

板凳
发表于 2009-1-6 23:22:00 | 只看该作者

#129:

{t² + 5t + 6}/7={(t+2)(t+3)}/7 而t is divided by 7, the remainder is 6,因此t+2/7余1,t+3/7余2,进而{(t+2)(t+3)}/7为余2.(一个余数乘另一个余数倒数,不确定,求证).

地板
发表于 2009-1-6 23:28:00 | 只看该作者
提示: 该帖被管理员或版主屏蔽
5#
发表于 2009-1-6 23:39:00 | 只看该作者
更正:也可能不被2的r次方整除
6#
发表于 2009-1-6 23:40:00 | 只看该作者
#197:同问? 谢谢.
7#
 楼主| 发表于 2009-1-7 01:48:00 | 只看该作者
以下是引用SHJDHKBB9在2009-1-6 23:10:00的发言:

#54: y is an integer

#93:答案是D.

(1)m 为 m - d 和m + d的中点.故m到m + d为68%/2=34%,然后所问为50-34=16%;

(2)m - d到m为50-16=34%,而m 为 m - d 和m + d的中点,因此m到m + d为34%,然后所问为50-34=16%.

所以选D.

谢谢SHJD啦~再看一遍54题,惭愧死

8#
 楼主| 发表于 2009-1-7 01:49:00 | 只看该作者
以下是引用SHJDHKBB9在2009-1-6 23:22:00的发言:

#129:

{t² + 5t + 6}/7={(t+2)(t+3)}/7 而t is divided by 7, the remainder is 6,因此t+2/7余1,t+3/7余2,进而{(t+2)(t+3)}/7为余2.(一个余数乘另一个余数倒数,不确定,求证).

“一个余数乘另一个余数倒数”??看不懂呀这是什么定理呢?


[此贴子已经被作者于2009-1-7 1:57:40编辑过]
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