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Math GWD 3- Q26

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楼主
发表于 2008-10-8 11:00:00 | 只看该作者

Math GWD 3- Q26

Q26:

(n-x) + (n-y) + (n-c) + (n-k)

What is the value of the expression above?

(1)     The average (arithmetic mean) of x, y, c, and k is n.

(2)     x, y, c, and k are consecutive integers.

                  

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.

答案A,我选E

有一点概念上的困惑。 (1)解出为5N,这算是可以确定的value么? N的值在这里也不确定啊。。难道N在这里可以算作常量?

沙发
发表于 2008-10-8 11:38:00 | 只看该作者
题目是说arithmetic mean of x, y, c, and k is n不是sum是n.

(n-x) + (n-y) + (n-c) + (n-k)的value是0,因为x+y+c+k=4n

板凳
发表于 2008-10-8 11:38:00 | 只看该作者
n-x+n-y+n-c+n-k=4n-(x+y+c+k)=4n-4n=0
地板
发表于 2008-10-10 11:19:00 | 只看该作者
  ls正解
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