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GWD18-Q36急,请高手指点!

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楼主
发表于 2008-5-6 04:58:00 | 只看该作者

GWD18-Q36急,请高手指点!

Q36:  
                    

If x and y are integers, is y an even integer?  A

      (1)     2yx = x2y2

(2)     x is an odd integer.

                  

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.

沙发
发表于 2008-5-6 07:21:00 | 只看该作者
2yx = x2y2 =>2y=x2+x – y=>2y=x(x+1)- y    

Since 2y is even,
x(x+1) --the product of 2 consecutive integer-- is even, then y must be even, so y is even.        

板凳
发表于 2008-5-6 07:44:00 | 只看该作者

2yx = x2y2 =>y(y+2)=x(x+1)

y and y+2 must be both odd or both even

x(x+1) must be even....thus y is even

地板
 楼主| 发表于 2008-9-1 21:24:00 | 只看该作者

谢谢二位及时回答,这道题的重点是怎样化简,和x(x+1)一定是偶数的应用!

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