lsat 1-6

lawyer_1

1.画三个圆.一个senator(S圆). 一个spoke at the convention(SC圆). 一个Democrat(D圆).

2.原文的一句话的一意思为:S圆和SC圆的交集一定是D圆的子集.

3.原文第二句话的意思为:S圆和SC圆的交集不是D圆的子集

4.2和3的意思是:S圆和SC圆不能相交.也就是选项D的意思.

5.原文两句话的逻辑关系分别是:S AND SC--->D.   S AND SC --->非D.意思是S AND SC不存在.即S不能和SC有AND的关系.即D的意思

ypngzhang

以下是引用lawyer_1在2006-12-23 3:40:00的发言：

1.画三个圆.一个senator(S圆). 一个spoke at the convention(SC圆). 一个Democrat(D圆).

2.原文的一句话的一意思为:S圆和SC圆的交集一定是D圆的子集.

3.原文第二句话的意思为:S圆和SC圆的交集不是D圆的子集

4.2和3的意思是:S圆和SC圆不能相交.也就是选项D的意思.

5.原文两句话的逻辑关系分别是:S AND SC--->D.   S AND SC --->非D.意思是S AND SC不存在.即S不能和SC有AND的关系.即D的意思

谢谢lawyer。终于明白了。

你对第二句话的解释太妙了！！我之前死活就是没转过这个弯来。lawyer就是lawyer阿 呵呵

还有个小小的问题，以后碰到 no A both B and C 这种情况，是不是就可以毫不犹豫地写成 B AND C --> 非A ?

[此贴子已经被作者于2006-12-23 7:36:28编辑过]

gracezz

以下是引用crusaders在2003/12/19 1:53:00的发言：
i am mindfree nn' fans
Pls allow me to show something interesting

L1 No senator spoke at the convention unless he or she was Democrat.
-(Senator + spoke) =-Democrat
----->If a senator spoke at the convention, he or she must be a Democrat.
------>Senator + spoke = Democrat
L2 No Democrat both spoke at the convention and was a senator.
-(Democrat + spoke) =Senator
----->ALL Democrat spoke at the convention was not a senator.
----->Democrat + spoke= -Senator

推导
Senator + spoke =Democrat
Democrat + spoke =-Senator
-------------------------------------------------------
Senator +spoke +spoke = -Sentor
2Senator=-2spoke
spoke=-Senator
senator=not + spoke

A.Spoke=Senator
B.Spoke=-Democrat
(迷惑选项)C.Only Democrats spoke at the convention.
从仅有的以知条件中推不出Democrats=spoke来.
D.Spoke=-Senator(答案)
E.Democratsenator=Spoke(无关)

这题解得这叫一个美呀~~~~~~~~~赞~~~~~~~~~~

白菜的白

强大

sudadelv

今天做到这个题了，见lawyer的分析，竟是6年之前，如醍醐灌顶，十分感谢啊！