LSAT-12-1-12

snow_mountain

12. In the Centerville Botanical Gardens, all
tulip trees are older than any maples. A
majority, but not all, of the garden's sycamores
are older than any of its maples. All the
garden's maples are older than any of its
dogwoods.
If the statements above are true, which one of
the following must also be true of trees in the
Centerville Botanical Gardens?
(A) Some dogwoods are as old as the youngest
tulip trees.
(B) Some dogwoods are as old as the youngest
sycamores.
(C) Some sycamores are not as old as the oldest
dogwoods.
(D) Some tulip trees are not as old as the oldest
sycamores.
(E) Some sycamores are not as old as the youngest
tulip trees.


答案是E。 没想明白。 照我的想法 Some sycamores are as old as the youngest
tulip trees. 也是成立的呀。

[此贴子已经被作者于2003-11-29 23:23:51编辑过]

Snazzy

hi, it seems for me there is some information missing or the description may be incorrect. according to the passage, i got the following fomula:
Tulip>Maple>Dogwoods. since most of sycamores, not all, r older than maples, and of course, some of them r younger or as young as maples. thus, answer E is wrong. on the contrary, i think B is the right answer.

What do u think?

snow_mountain

i copy and paste the question from ELSAT. so who can check the orignial question and answer for me?

by the way, think B may be correct, but not must be so.
your formula is correct.  since some r are older than any maple. but not all of them.

the formula can also be Tulip>some sycamores> Maple>Dogwoods  and
                                 Tulip> Maple>other sycamores>Dogwoods  

in such case, B is wrong.  

what do u think?

cranberry

e 是正确的,maplesmaples,so there must be some sy which are younger than some maples,and all the maples are younger than any tulip,so there must be some sy younger than any tulip

snow_mountain

明白了。谢谢。