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1. (1) [x,y] = [2,2] & [3,2] though fulfill requirement but results contradict each other
(2) x,y are not specified to be odd or even
together, prime>7 is always odd thus make y+1 always even, therefore x(y+1) is made always even.
2.500 is the multiple of 100 that is closest to X => 450<X<550
400 is the multiple of 100 that is closest to Y => 350<Y<450
so 800<X+Y<1000, one of 800, 900, 1000 will be multiple of 100 is closest to X+Y
(1) X<500,=> 800<X+Y<950, either 800 or 900 will be multiple of 100 is closest to X+Y
(2) Y<400 => same as above
together => 800<X+Y<900, either 800 or 900 will be multiple of 100 is closest to X+Y as we cannot confine X+Y to any smaller intervals (if within 50, we may probably solve this question)
3. need hard work to calculate 30! ? no!
we have 5,10,15,20,25,30 and some 2s to see how many zeros there are in the tail of the result
5x2, 15x2 contributes 1 zero each
10, 20, 30 => 3 zeros
25x4 => be careful, it contributes 2 zeros
so totally there are 1x2+3+2=7 zeros in the tails of 30!
for (1) d can be 1,2,3,4,5,6,7 (2) d can be any integer >6
together, d can only be 7 to fulfill both requirements.
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