求问两题JJ余数

路人甲

zimochen 发表于 2015-9-28 15:00
Mark一下！

如果求余数是多少就需要那个29了，可以说下那个29怎么出来的吗。

zimochen

路人甲 发表于 2015-10-4 00:31
如果求余数是多少就需要那个29了，可以说下那个29怎么出来的吗。

亲，我不明白你问的啥？你是不是问错人了。。。

路人甲

zimochen 发表于 2015-10-4 00:39
亲，我不明白你问的啥？你是不是问错人了。。。

问错啦哈哈

olinak

谢谢谢谢~~lz的问题也是我的问题！

julie0808

thewong 发表于 2015-10-1 22:49
Mark一下！

亲你知道为什么N=30k+X了么

xenaliu

解答怎样得到30k+29

两个式子：n=5k+4, n=6k+5

Positive integer n is divided by 5, the remainder is 4 --> n=5a+4, where a is the quotient --> 4, 9, 14, 19, 24, 29, ...
Positive integer n is divided by 6, the remainder is 5 --> n=6b+5, where b is the quotient -->5, 11, 17, 23, 29 , ....

There is a way to derive a general formula for n (of a type n=kx+r, where x is divisor and r is a remainder) based on the above two statements:

Divisor x would be the least common multiple of above two divisors 5 and 6, hence x=30.

Remainder r would be the first common integer in above two patterns, hence r=29.

Therefore general formula based on both statements is n=30k+29.