明天上战场,求问一道数学JJ~~~338

jessecha

338.f(x)=f(x-1) b, f(0)=a, a,b 都是常数，求f(2^1) (原题x什么的用的是下标，反正无所谓），选a 2b


狗主的答案对吗? 还请哪位留下具体解法过程啊. 谢谢了

sdcar2010

f(0)  = a

f(2) = f(2-1) + b  = f(1) + b = [f(1-1) + b] + b = f(0) + 2b = a + 2b

jessecha

f(0)  = a

f(2) = f(2-1) + b  = f(1) + b = [f(1-1) + b] + b = f(0) + 2b = a + 2b

-- by 会员 sdcar2010 (2011/8/18 9:44:05)

Thx a lot