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求NN解答:一道CR

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楼主
发表于 2008-9-12 16:06:00 | 只看该作者

求NN解答:一道CR

Often patients with ankle fractures that are stable, and thus do not
        
require surgery, are given follow-up x-rays because their orthopedists
        
are concerned about possibly having misjudged the stability of the fracture. When a number of follow-up x-rays were reviewed, however, all
        
the fractures that had initially been judged stable were found to have
        
healed correctly. Therefore, it is a waste of money to order follow-up x-rays of ankle fracture initially judged stable.

 问加强

答案是

.C.      X-rays of patients of many different orthopedists working in several
        
hospitals were reviewed.

为什么啊?~~~~~谢谢!

沙发
发表于 2008-9-12 23:08:00 | 只看该作者
可否把别的选项贴出来,C不像答案。因原文结论是x-ray waste money, C选项不太靠谱
板凳
发表于 2008-9-12 23:44:00 | 只看该作者

这个是GWD里的CR吗?

我记得这道题目的争论还挺大的,最后好象说选C是由于C说骨折拍片因为去了许多 不同的 医院,所以浪费了钱...

但是我今天再看这个题觉得可以这么想:

文章说

 When a number of follow-up x-rays were reviewed, however, all
    
the fractures that had initially been judged stable were found to have
    
healed correctly. Therefore, it is a waste of money to order follow-up x-rays of ankle fracture initially judged stable.

When a number of follow-up x-rays were reviewed 是 waste of money 推断成立的前提,

C.X-rays of patients of many different orthopedists working in several
     
hospitals were reviewed=When a number of follow-up x-rays were reviewed

相当于承认了推论前提存在,使得推论成立的可能性增强,因此加强

当然这是我个人看法

希望大家批判指正~


[此贴子已经被作者于2008-9-12 23:44:52编辑过]
地板
发表于 2008-9-13 00:35:00 | 只看该作者

D)    The healing of ankle fractures that have been surgically repaired is always checked by means of a follow-up x-ray.

找到的D选项应该是正解->x-ray 后才有 healing

5#
发表于 2008-9-13 00:42:00 | 只看该作者
哦,C是驳斥啊
6#
发表于 2008-9-13 01:32:00 | 只看该作者

这个GWD在逻辑区争论的还挺火的,

正确答案好像是谈样本的充分性。

7#
发表于 2008-9-13 09:44:00 | 只看该作者

个人认为D是无关

D 说的是The healing of ankle fractures that have been surgically repaired

题目中说的是patients with ankle fractures that are stable, and thus do not
                    
require surgery,
                

out of scope 了

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