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求解一道GWD数学~谢谢大家~

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楼主
发表于 2012-9-10 13:53:05 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day.If r percent of the store’s revenues from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of newspaper B, which of the following expresses r in terms of p?



A.100p / (125 – p)

B.150p / (250 – p)

C.300p / (375 – p)

D.400p / (500 – p)

E.500p / (625 – p)
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沙发
发表于 2012-9-10 14:40:26 | 只看该作者
这题似乎以前讨论过,是有问题的,这里都说了no other newspapers that day.  那r+p肯定=1吖
那r=1-p呀,题目不对的
板凳
发表于 2012-9-10 14:52:28 | 只看该作者
4-4p/ p+4   我咋算出这个来了?没有答案啊
地板
发表于 2012-9-10 14:53:44 | 只看该作者
看清题目,r是 关于revenue的  p 是销售数量
5#
 楼主| 发表于 2012-9-10 14:55:10 | 只看该作者
有人说是设总量为100 A的数量就是p 这个我就没理解~ 我觉得A的数量应该是r才对~
6#
 楼主| 发表于 2012-9-10 15:15:49 | 只看该作者
有没有大神帮我解答啊` x偶已经要崩溃了~
7#
发表于 2012-9-10 15:22:44 | 只看该作者
看错了~=。=这题没错,设A、B报纸非别卖了A、B份,则有r/100=A/(A+1.25B)   p/100=B/(A+B)
由后一个式子可以得出A=(100-P)B/p  代入第一个式子,化简出来,比较复杂,但B可以消掉,答案就是D。。
8#
 楼主| 发表于 2012-9-10 16:01:38 | 只看该作者
我化简到r=100(100-p)/100-0.25p 就化简不下去了~
9#
发表于 2012-9-10 16:13:26 | 只看该作者
其实还好啊~慢慢化简 这个还不是很烦的 是不是哪里出错了=。=
10#
发表于 2012-9-10 16:39:55 | 只看该作者
我化简到r=100(100-p)/100-0.25p 就化简不下去了~
-- by 会员 zhangtysun (2012/9/10 16:01:38)

不要忧伤 我来救你??!!!
正确题目如下:
Last Sunday a certain store sold copies of Newspaper Afor $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day.  If r percent of the store’s revenues from newspaper sales was from Newspaper A
and if p percent of the newspapers that the store sold were copies ofnewspaper A, which of the followingexpresses r in terms of p?
A.   100p / (125 – p)
B.    150p / (250 – p)
C.    300p / (375 – p)
D.    400p / (500 – p)
E.    500p / (625 – p)

你列式子无问题,此楼题目稍不对。
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