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If 10^50 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer? A. 424 B. 433 C. 440 D. 449 E. 467
10^3 = 1000 [4 digits] 10^5 = 100000 [6 digits]
similarly, 10^50 = 1000....[51 digits]
1000 - 74 = 926 100000 - 74 = 99926
10^50 - 74 = 99999999......26
Therefore the sum of the digits = 9*48 = 432 + 2 + 6 = 440.
Hope this helps. |
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